Simulate and plot the liquid level in the tank โ„Žโ€ฒ(๐‘ก)versus time for the uncontrolled process

Problem 2.Consider the stirred tank vessel from Problem 1 of Tutorial 5.Up to time 0 the process is at steady state. At time 0 there is a step change in the influent flow rate, i.e. ๐น๐‘–(๐‘ก)increases by 0.001 m3/s.Using Simulink for the simulations, carry out the following:a)Build in Simulinkthe closed loop block-diagram for the controlled process, using a generic PI transfer function and the transfer functions for the process, the control valve and the measuring device as determined in Tutorial 5. Use โ€œScopeโ€ blocks to visualise and export the profiles of the liquid level, โ„Žโ€ฒ(๐‘ก), the error ๐œ€(๐‘ก), the controller output ๐‘โ€ฒ(๐‘ก), and the manipulated variable ๐น๐‘œโ€ฒ(๐‘ก). For the controller, use a generic PID block and define the Form as โ€œIdealโ€ and the Time domain as โ€œContinuous-timeโ€.b)Simulate and plot the liquid level in the tank โ„Žโ€ฒ(๐‘ก)versus time for the uncontrolled process (i.e. with all the parameters of the PI controller set to 0).c)Using the P control action alone simulate and plot the liquid level in the tankโ„Žโ€ฒ(๐‘ก)with๐พ๐‘values in the range 0 โˆ’(-1) atm/m. Discuss the results.d)Starting from the closed loop response equation for the process, calculate the offset for the various ๐พ๐‘values considered in c). Compare the calculated values with those predicted by Simulink and discuss trends in relation to theory.e)Using PI control, simulate and plot the liquid level in the tank for ๐พ๐‘=โˆ’1atm/m and ๐œ๐›ช=20s. Notethat Simulink uses the reciprocal of ๐œ๐›ช, ๐ผ,called reset rate, therefore in Simulink we have to use ๐ผ=0.05s-1.Compare and discuss the response of the PI controller with the one of the P controller.

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